Respuesta :
Use the table to draw the graph of height(y-axis) against week(x-axis).
The graph is a straight line.
Find the gradient of the graph as the first step.
Gradient = (y2-y1)/(x2-x1)
= (17-12)/(4-2)
= 5/2
Use this gradient to find the equation of the line. Use one of the point from the table (e.g. (8,27)) and another general point (x,y).
∴5/2=(y-27)/(8-x)
5/2 (x-8) = y-27
(5/2)x - 20 = y-27
y=(5/2)x - 20 + 27
y = (5/2)x + 7
The answer is A
The graph is a straight line.
Find the gradient of the graph as the first step.
Gradient = (y2-y1)/(x2-x1)
= (17-12)/(4-2)
= 5/2
Use this gradient to find the equation of the line. Use one of the point from the table (e.g. (8,27)) and another general point (x,y).
∴5/2=(y-27)/(8-x)
5/2 (x-8) = y-27
(5/2)x - 20 = y-27
y=(5/2)x - 20 + 27
y = (5/2)x + 7
The answer is A
Answer:
y = [tex] \frac{5}{2} x + 7[/tex]
Explanation:
The general form of the linear equation is:
y = mx + c
where:
m is the slope
c is the y-intercept
1- getting the slope:
slope can be calculated as follows:
m = [tex] \frac{y2 - y1}{x2 - x1} [/tex]
I will use the points (2,12) and (8,27) to get the slope. You can choose any other two points and you will get the same answer.
m = [tex] \frac{27-12}{8-2} = \frac{5}{2} [/tex]
The equation of the line now is:
y = [tex] \frac{5}{2} x + c[/tex]
2- getting the y-intercept:
To get the y-intercept (c), we will use any of the given points, substitute in teh equation and solve for c.
I will use the point (6,22) as follows:
y = [tex] \frac{5}{2} x + c[/tex]
22 = [tex] \frac{5}{2} (6) + c[/tex]
22 = 15 + c
c = 7
Based on teh above, the equation of the line is:
y = [tex] \frac{5}{2} x + 7[/tex]
Hope this helps :)
y = [tex] \frac{5}{2} x + 7[/tex]
Explanation:
The general form of the linear equation is:
y = mx + c
where:
m is the slope
c is the y-intercept
1- getting the slope:
slope can be calculated as follows:
m = [tex] \frac{y2 - y1}{x2 - x1} [/tex]
I will use the points (2,12) and (8,27) to get the slope. You can choose any other two points and you will get the same answer.
m = [tex] \frac{27-12}{8-2} = \frac{5}{2} [/tex]
The equation of the line now is:
y = [tex] \frac{5}{2} x + c[/tex]
2- getting the y-intercept:
To get the y-intercept (c), we will use any of the given points, substitute in teh equation and solve for c.
I will use the point (6,22) as follows:
y = [tex] \frac{5}{2} x + c[/tex]
22 = [tex] \frac{5}{2} (6) + c[/tex]
22 = 15 + c
c = 7
Based on teh above, the equation of the line is:
y = [tex] \frac{5}{2} x + 7[/tex]
Hope this helps :)