Question

How do you find the x-intercepts of
$y = 12x + {7x}^{2}$
Please help!!

Answer 1

x - intercepts → y = 0

$y=12x+7x^2\to12x+7x^2=0\\\\x(12+7x)=0\iff x=0\ \vee\ 12+7x=0\\\\x=0\ \vee\ 7x=-12\\\\x=0\ \vee\ x=-\dfrac{12}{7}$

Answer: $x=0;\ x=-\dfrac{12}{7}$