Respuesta :

[tex]\frac{-(x-2)}{6} - \frac{3(3x+2)}{6} \\ \math{\frac{2-x}{6} - \frac{9x + 6}{6}} \\ \math{\frac{-4-10x}{6}} \\ \math{\frac{-2(2+5x)}{6}} \\ \math{\frac{-(2+5x)}{3}}[/tex]

Answer:

−5/3x + −2/3

Step-by-step explanation:

−1/6x + 1/3+ −3/2x + −1

=−1/6x + 1/3+ −3/2x + −1

=(−1/6x + −3/2x) + (1/3 + −1)

=−5/3x + −2/3

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