Answer:
[tex]51\°[/tex]
Step-by-step explanation:
we know that
[tex]sec(x)=\frac{1}{cos(x)}[/tex]
In this problem we have
[tex]sec(x)=1.6[/tex]
so
[tex]x=arcsec(1.6)[/tex] -----> equation A
[tex]1.6=\frac{1}{cos(x)}[/tex]
[tex]cos(x)=\frac{1}{1.6}[/tex]
[tex]x=arccos(\frac{1}{1.6})[/tex] ---> equation B
equate equation A and equation B
[tex]arcsec(1.6)=arccos(\frac{1}{1.6})[/tex]
[tex]arcsec(1.6)=51\°[/tex]
