Respuesta :
8 “choose” 5 = (8! / 5! x (8 - 5) ! )
8 “choose” 5 = (8! / 3! x 5!)
= (8 x 7 x 6 x 5 x 4 x 3 x 2 x 1) /
(5 x 4 x 3 x 2 x 1) /
(3 x 2 x 1)
= (8 x 7 x 6) /
(3 x 2 x 1)
= ( 7 x 4 x 2) = 56
Therefore there are 56 ways 5 singers can be selected from 8 that came to an audition.
8 “choose” 5 = (8! / 3! x 5!)
= (8 x 7 x 6 x 5 x 4 x 3 x 2 x 1) /
(5 x 4 x 3 x 2 x 1) /
(3 x 2 x 1)
= (8 x 7 x 6) /
(3 x 2 x 1)
= ( 7 x 4 x 2) = 56
Therefore there are 56 ways 5 singers can be selected from 8 that came to an audition.
Answer: There are 56 ways to choose 5 singers from 8 singers.
Step-by-step explanation:
Since we have given that
Number of total singers = 8
Number of singers to be selected = 5
So, we will use "Combination":
So, number of ways to choose 5 singers from 8 singers is given by
[tex]^8C_5\\\\=\dfrac{8\times 7\times 6}{3\times 2\times 1}\\\\=56[/tex]
Hence, there are 56 ways to choose 5 singers from 8 singers.