Question

What is the domain of the function y=sqrt x+4

Answer 1

$\text{if}\ y=\sqrt{x}+4\ \text{then the domain is}\ x\geq0\to x\in\mathbb{R^+}\cup\{0\}$


$\text{if}\ y=\sqrt{x+4}\ \text{then the domain is}\ x+4\geq0\to x\geq-4\to x\in\left<-4;\ \infty\right)$

Answer 2

Answer:

Domain of $\sqrt{x+4}$ is [-4,∞)

Step-by-step explanation:

We have to find domain of $\sqrt{x+4}$

We know that the square root value of negative numbers are not defined.

So we should not give negative numbers inside square root.

That is

         $x+4\geq 0\\\\x\geq -4$

Domain of $\sqrt{x+4}$ is [-4,∞)