Question

For the reaction: h2(g) + cl2(g) → 2hcl(g), how many moles hcl will be produced from 10.0 g of h2? the reaction occurs in the presence of excess cl2

Answer 1

Answer : The moles of HCl produced will be, 10 moles

Explanation : Given,

Mass of $H_2$ = 10 g

Molar mass of $H_2$ = 2 g/mole

First we have to calculate the moles of $H_2$.

$\text{Moles of }H_2=\frac{\text{Mass of }H_2}{\text{Molar mass of }H_2}=\frac{10g}{2g/mole}=5moles$

Now we have to calculate to moles of HCl.

The given balanced chemical reaction is,

$H_2(g)+Cl_2(g)\rightarrow 2HCl(g)$

From the balanced chemical reaction, we conclude that

As, 1 mole of $H_2$ react to give 2 moles of HCl

So, 5 mole of $H_2$ react to give $2\times 5=10$ moles of HCl

Therefore, the moles of HCl produced will be, 10 moles

Answer 2

"10 moles" of HCl will be produced.

Given reaction,

• $H_2 (g) +Cl_2 (g) \rightarrow 2HCl(g)$

Given values,

• Mass of H₂ = 10 g
• Molar mass of H₂ = 2 g/mole

The moles of H₂ will be:

= $\frac{Mass}{Molar \ mass}$

= $\frac{10}{2}$

= $5 \ moles$

According to the given reaction, 1 moles of H₂ reacts to give 2 moles of HCL.

hence,

5 mole of H₂ reacts,

= $2\times 5$

= $10 \ moles$

Thus the above answer is right.

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