when ΔH = -445.1 KJ/mol (given) missing in your question.
and this value is per mole NaOH.
∴ the amount of heat = ΔH / mol NaOH * (mass NaOH) (1 mol NaOH / molar mass NaOH)
by substitution:
= -445.1 KJ/mol / mol NaOH * 1 g NaOH * 1molNaOH /40 g NaOH
= -11.1 KJ