Question

3h/h^2-12h+36 -18/h^2-12h+36

Answer 1

Since both fractions have the same denominator, we just need to subtract the numerators:
$\frac{3h}{h^2-12h+36} - \frac{18}{h^2-12h+36} = \frac{3h-18}{h^2-12h+36}$

Notice that we have a common factor, 3, in the numerator, so lets factor that out:
$\frac{3h-18}{h^2-12h+36}= \frac{3(h-6)}{h^2-12h+36}$

Next, we can factor the denominator:
$\frac{3(h-6)}{h^2-12h+36} = \frac{3(h-6)}{(h-6)^2}$

Now we can cancel the common factor $h-6$ in both numerator and denominator:
$\frac{3(h-6)}{(h-6)^2}= \frac{3}{h-6}$

We can conclude that the result of 3h/h^2-12h+36 -18/h^2-12h+36 is: $\frac{3}{h-6}$

Answer 2

The equation: 3h/h^2-12h+36 -18/h^2-12h+36 have the same denominator, we will just subtract the numerators
3h/h^2-12h+36- 18/h^2-12h+36=3h-18/h^2-12h+36
Let us factor the common termsx(h-6)/h^2-12h+36= 3(h-6)/(h-6)^2
So since h-6 are similar, we can cancel the numerator and cancel 1 term in the denominatorso,3(h-6)/(h-6)^2=3/h-6
SO the answer of 3h/h^2-12h+36 -18/h^2-12h+36  is 3/h-6