Question

HELP PLEASE!!!
Base your answer to the question on the diagram shown below.

Fernando is going to draw a marble from the bag, replace it, and then draw another marble. What is the probability that Fernando will get a green or blue marble on the first draw and a pink on the second draw?



(3 green, 4 yellow, 5 blue, 8 pink)

1.) 4/5
2.) 4/25
3.) 3/100

Answer 1

The answer is actually the second choice 4/25 hope this helps...

Answer 2

Answer:  The correct option is (2) $\dfrac{4}{25}.$

Step-by-step explanation:  Given that there are 3 green, 4 yellow, 5 blue and 8 pink marbles in a bag. Fernando is going to draw a marble from the bag, replace it, and then draw another marble.

We are to find the probability that Fernando will get a green or blue marble on the first draw and a pink on the second draw.

Let, S be the sample space for the experiment of drawing a marble from  the bag.

Then, n(S) = 3 + 4 + 5 + 8 = 20.

Let E denotes the event of drawing a green or blue marble and F denote the event of drawing a pink marble.

Then, we have

n(E) = 3 + 5 = 8   and   n(F) = 8.

Since the second marble is drawn after replacing the first marble,

so the required probability of Drawing a green or blue marble on the first draw and a pink marble on the second draw is

$P\\\\=P(E)\times P(F)\\\\\\=\dfrac{n(E)}{n(S)}\times \dfrac{n(F)}{n(S)}\\\\\\=\dfrac{8}{20}\times\dfrac{8}{20}\\\\\\=\dfrac{4}{25}.$  

Thus, the required probability is $\dfrac{4}{25}.$

Option (2) is CORRECT.