Respuesta :

The least common denominator has the highest degree of each of the variables and the LCM of the constants as factors.
Ver imagen sqdancefan

Answer:

1st Tile = 144m²n³

2nd tile = [tex]72m^{4}n^{4}[/tex]

3rd tile = [tex]36m^{3}n[/tex]

4th tile = [tex]48m^{4}n^{4}[/tex]

Step-by-step explanation:

In this question we have to find out the least common multiple of the denominators and pair them with the rational expressions.

LCM of 9m²n and 16mn²

prime factors of 9m²n = 3×3×m×m×n

prime factors of 16mn³ = 2×2×2×2×m×n×n×n

So LCM of both = 2×2×2×2×3×3×m×m×n×n×n = 144 m²n³

LCM of [tex]8m^{4}n^{2}, 18m^{2}n^{4}[/tex]

prime factors of [tex]8m^{4}n^{2}[/tex] = 2×2×2×m×m×m×m×n×n

prime factors of [tex]18m^{2}n^{4}[/tex] = 2×3×3×m×m×n×n×n×n

LCM of both = 2×2×2×3×3×m×m×m×m×n×n×n×n = [tex]72m^{4}n^{4}[/tex]

Similarly LCM of [tex]12mn, 18m^{3}n[/tex] will be [tex]36m^{3}n[/tex]

LCM of [tex]24mn^{4}, 16m^{4}n[/tex] will be [tex]48m^{4}n^{4}[/tex]