Respuesta :
[tex](\sqrt[n]{a})^m=a^\frac{m}{n}[/tex]
[tex]-32^\frac{3}{5}=(\sqrt[5]{-32})^3=(-2)^3=-8[/tex]
[tex]\sqrt[5]{-32}=-2\ because\ (-2)^5=-32[/tex]
[tex]-32^\frac{3}{5}=(\sqrt[5]{-32})^3=(-2)^3=-8[/tex]
[tex]\sqrt[5]{-32}=-2\ because\ (-2)^5=-32[/tex]
Answer:
its -8 man.... come on guys lol!
Step-by-step explanation: