Question

Jason would like to estimate the probability of heads coming up more than once in 3 coin flips. To do this, he has a computer randomly select 0 or 1 three times, with 0 representing heads and 1 representing tails. The results of 10 trials are shown in the table. 110 111 100 000 101 111 100 000 011 010 What is Jason's estimated probability, based on this simulation? Enter your answer as a fraction, in simplified form, in the box.

Answer 1

The total number of tries = 10

The tries are  { 110 111 100 000 101 111 100 000 011 010  }

Where: 0 representing heads and 1 representing tails

The tries which are heads came up more than once in 3 coin flips { 100 000 100 000 010  }

The number of the tries which are heads came up more than once in 3 coin flips = 5

∴ The probability of heads coming up more than once in 3 coin flips = 5/10 = 1/2

Answer 2

the correct answer is $\frac{1}{2}$