Respuesta :
To solve this problem you must apply the proccedure shown below:
1. You have the following information given in the problem above: The leg AC has length 18, the leg BC has length 24, and the hypotenuse AB has length 30.
2. Therefore, you have:
- You have that SinA is:
SinA=Opposite/Hypotenuse
SinA=24/30
SinA=4/5
- You have that CosA is:
CosA=Adjacent/Hypotenuse
CosA=18/30
CosA=3/5
1. You have the following information given in the problem above: The leg AC has length 18, the leg BC has length 24, and the hypotenuse AB has length 30.
2. Therefore, you have:
- You have that SinA is:
SinA=Opposite/Hypotenuse
SinA=24/30
SinA=4/5
- You have that CosA is:
CosA=Adjacent/Hypotenuse
CosA=18/30
CosA=3/5
Although there i no triangle given as the question requires, I am still going to answer because I understand it.
ABC is a right angled triangle. The triangle is 90° at C.
The trigonometric ratio sine is given by, sine = opposite/hypotenuse .
Cosine = adjacent/hypotenuse
So therefore, Sin A = 24/30
= 4/5
Cos A = 18/30
= 3/5
ABC is a right angled triangle. The triangle is 90° at C.
The trigonometric ratio sine is given by, sine = opposite/hypotenuse .
Cosine = adjacent/hypotenuse
So therefore, Sin A = 24/30
= 4/5
Cos A = 18/30
= 3/5