Answer:
128 g of Li will react with 86.1 g of N₂ to completely consume it.
Solution:
The balance chemical equation is as follow,
6 Li + N₂ → 2 Li₃N
According to this equation,
28 g (1 mole) N₂ reacts with = 41.64 g (6 moles) of Li
So,
86.1 g of N₂ will react with = X g of Li
Solving for X,
X = (86.1 g × 41.64 g) ÷ 28 g
X = 128 g of Li
