Find the coordinate of the point (x,y) shown on the unit circle
![Find the coordinate of the point xy shown on the unit circle class=](https://us-static.z-dn.net/files/daf/f17ae1a687175f034e6b89530607ca4f.png)
Here the angle is
[tex]\frac{4 \pi}{3}[/tex]
And radius is 1 units .
And
[tex]x = r cos \theta, y = r sin \theta[/tex]
Substituting the values of theta and r, we will get
[tex]x = 1 cos(\frac{4 \pi}{3} ) = -1/2 \\ y=1 sin( \frac{4 \pi}{3} ) =\sqrt3 /2[/tex]
So we will get
[tex]x = \frac{-1}{2} , y = -\frac{ \sqrt 3}{2}[/tex]
The coordinate of the point (x,y) shown on the unit circle is therefore: (-1/2, -√3/2)
The circle given is a unit circle.
In essence, the radius as indicated by the blue line is 1.
The angle subtended by the line is; 4π/3.
Therefore, from trigonometry of right-angled triangles; we have;
where, r = 1
Therefore,
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