Respuesta :
Answer:
There are no x-values that gives such result.
Step-by-step explanation:
The given function is
[tex]f(x)=-0.5|2x+2|+1[/tex]
To find the values that gives [tex]f(x)=6[/tex], we replace this
[tex]6=-0.5|2x+2|+1[/tex]
Then, solve for [tex]x[/tex]
[tex]6-1=-0.5|2x+2|\\5=-0.5|2x+2|\\-\frac{5}{0.5}=|2x+2|\\ |2x+2|=-10[/tex]
There are two ways
[tex]2x+2=-10[/tex] and [tex]2x+2=10[/tex]
The first solution is
[tex]2x=-10-2\\x=\frac{-12}{2}\\ x=-6[/tex]
The second solution is
[tex]2x=10-2\\x=\frac{8}{2}\\ x=4[/tex]
Let's evalue the initial function for these values
[tex]f(-6)=-0.5|2(-6)+2|+1=-0.5|-12+2|+1=-0.5(10)+1=-5+1=-4\\f(4)=-0.5|2(4)+2|+1=-0.5|8+2|+1=-0.5(10)+1=-5+1=-4[/tex]
Therefore, there are no x-values that gives such result.