Question

In the reaction 2RbNO3 → 2RbNO2 + O2, how many moles of O2 are produced when 5.0 mol of RbNO3 decompose?

Answer 1

the balanced equation for the reaction is as follows
2RbNO₃ --> 2RbNO₂ + O₂
stoichiometry of RbNO₃ to O₂ is 2:1
number of moles of RbNO₃ decomposed - 5.0 mol
when 2 mol of RbNO₃ decomposes, 1 mol of O₂ is formed 
therefore when 5.0 mol of RbNO₃ decomposes - 5.0 / 2 = 2.5 mol of O₂
2.5 mol of O₂ is formed 

Answer 2

The number of moles of O2 that would be produced from the decomposition of 5 moles of RbNO3 according to the reaction will be 2.5 moles.

From the balanced equation of the reaction, for every 2 moles of RbNO3 that decomposes, 1 mole of O2 is produced.

Now, if 5 moles of RbNO3 decomposes, the mole of O2 that would be produced can be calculated as:

mole = 5 x 1/2

                = 2.5 moles

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