Question

Write the standard form of the equation of the circle with the given center and radius.

(-3, 6); 10

Answer 1

The std eqn is  (x-h)^2 + (y-k)^2 = r^2.

Here we have   (x+3)^2 + (y-6)^2 = 10^2    (answer)

Answer 2

Answer:

A circle with center at (-3, 6) and a radius of 10 has the following standard form equation

$(x+3)^2+(y-6)^2=100$

Step-by-step explanation:

This is the general standard equation for the circle centered at (h, k) with radius r

$(x-h)^2+(y-k)^2=r^2$

It shows all the important information at a glance: the center (h, k) and the radius r.

A circle with center at (-3, 6) and a radius of 10 has the following standard form equation

Start with:

$(x-h)^2+(y-k)^2=r^2$

Put in (h, k) and r

$(x-(-3))^2+(y-6)^2=10^2\\(x+3)^2+(y-6)^2=100$