Respuesta :
the atomic mass of Phosphorous is 31. the molar mass is numerically equivalent to the atomic mass.
the molar mass of P is 31 g/mol
1 mol of P is made of 6.022 x 10²³ atoms of P.
this means that 31 g is made of 6.022 x 10²³ atoms of P.
therefore in 172.90 g there are - 6.022 x 10²³ / 31 x 172.90 = 3.359 x 10²⁴ atoms
there are 3.359 x 10²⁴ atoms of P
the molar mass of P is 31 g/mol
1 mol of P is made of 6.022 x 10²³ atoms of P.
this means that 31 g is made of 6.022 x 10²³ atoms of P.
therefore in 172.90 g there are - 6.022 x 10²³ / 31 x 172.90 = 3.359 x 10²⁴ atoms
there are 3.359 x 10²⁴ atoms of P
The atoms of phosphorus (P) that are in a sample, which has a mass of 172.90 grams is 33.54x10²³.
How many atoms are present in 1 mole of any substance?
No. of atoms in one mole of any substance will define by the Avogadro's number and its value is 6.022 x 10²³, it means in one mole of substance 6.022 x 10²³ atoms are present.
Mole of phosphorous will be calculated as:
n = W/M, where
W = given mass of phosphorous = 172.90 g
M = molar mass of phosphorous = 31g/mole
Moles of phosphorous = 172.90/31 = 5.57 moles
No. of atoms in 5.57 moles of phosphorous = 5.57 × 6.022x10²³ = 33.54x10²³
Hence the required number of atoms are 33.54x10²³.
To know more about Avogadro's number, visit the below link:
https://brainly.com/question/1528951
