What does Raoult's law state?

a. The vapor pressure of a pure solvent is higher than that of a solution containing that solvent.

b. The vapor pressure of a pure solvent is lower than that of a solution containing that solvent.

c. The vapor pressure of a solute is the same as the vapor pressure of the solvent.

d. The vapor pressure of a solute is greater than that of a pure solvent.

Respuesta :

PBCHEM
Correct Answer is A:  The vapor pressure of a pure solvent is higher than that of a solution containing that solvent.

Reason
According to Raoult's Law states that v
apor pressure of each component in the solution is equal to the vapor pressure of the pure component multiplied by its mole fraction. It is mathematically expressed as
P = X 
[tex] P^{0} [/tex]
where, P = vapor pressure of solution
X = mole fraction of solute
P^{0} [/tex] = vapor pressure of pure component

Here X is always less than one (in solutions)

∴ P < P^{0} [/tex]

Raoult's law states That the vapor pressure of a pure solvent is higher than that of a solution containing that solvent. This is law of thermodynamics established by French chemist François-Marie Raoultin in 1887. This shows that  partial vapor pressure  is equal to the vapour pressure.
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