Question

What are the zeros of the function? f(x)=x3−2x2−3x

Answer 1

-1, 0, 3

You can get this by factoring. The fully factored version of this is 

x(x - 3)(x +1)

Then set each of the 3 parts equal to zero. 

Answer 2

The zeros of the given function $f(x)=x^3-2x^2-3x$ would be -1, 0, and 3.

How to find zeros and y-intercept of a function?

Zeros =Intersection points of the considered function's curve on the input axis(usually represented by values of x)

y-intercept = Intersection points of the considered function's curve on the output axis

On the x-axis, value of the y-coordinate is 0,

On the y-axis, the value of the x-coordinate is 0.

Thus, if function is

y=f(x)

then putting y = 0 gives zeros of the function.

And putting x = 0 gives the y-intercept of the function. (if any, for both cases).

The given function is

$f(x)=x^3-2x^2-3x$

The zeros of the function

$x(x^2-2x-3)\\\\x(x^2-(3-1)x-3)\\\\x(x^2-3x+x-3)\\\\x(x - 3)(x +1)$

Then, set each of the 3 parts equal to zero.

Learn more about finding the solution here:

https://brainly.com/question/26254258

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