Question

Identify the height of a triangle in which b = (x − 2) m and A = (x2 − 4) m2.

Answer 1

Answer:

h=(2x+4)m

Step-by-step explanation:

It is given that b=(x−2) m and A=(x^2−4) m^2

To calculate the area of this triangle, substitute these given values for b and A into the formula for the area of a triangle A=1/2bh, then solve for the unknown h.

x^(2)-4=(1)/(2)(x-2)h

Multiply by 2

2x^2-8=h(x-2)

Divide by (x-2)

2x^2-8/x-2=h

Solve for h

h=(2x+4)m

Hope this helps you!

Answer 2

Area of the triangle is the area occupied by a triangle. The height of the triangle can be written as 2(x+2).

What is the area of the triangle?

The area of the triangle is given by the formula,

$Area = \dfrac{1}{2}\times b\times h$

The area of the triangle is given to us  A = (x²−4) meter², also the length for the base of the triangle is also given to us b=(x−2) meter. Therefore, the length of the base of the triangle can be given as,

$Area = \dfrac{1}{2}\times b\times h$

Substitute the values,

$(x^2-4) = 0.5 \times (x-2) \times h\\\\h = \dfrac{2(x^2-4)}{(x-2)}\\\\h = \dfrac{2(x^2-2^2)}{(x-2)}\\\\\h = \dfrac{2(x-2)(x+2)}{(x-2)}\\\\h=2(x+2)$

Hence, the height of the triangle can be written as 2(x+2).

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