Question

The number of bacteria present in a culture after t minutes is given as where k is a constant. if there are 8520 bacteria present after 15 minutes, find k and round to the nearest thousandth.


a. 0.143


c. 2.143


b. 32.136


d. 0.13 brainly

Answer 1

Given that the situation has been modeled by the formula:
B=1000e^(kt)
given that B=8520 after t=15 min
then the value of k will be solved as follows:
plugging in the values in the formula and solving for k
8520=1000e^(15k)
8.52=e^(15k)
solving for k
15k=ln(8.52)
hence
k=ln(8.52)/15
k=0.1428
k=0.143

Answer 2

Answer:

option:A

Step-by-step explanation:

We are given that the problem is modeled with the help of a function

$G(t)=1000e^{kt}$

now we are given that $G=8520$ at $t=15min$

now we need to find the value of k with the help of the given condition

hence putting the value of G using the given equation we get that

$8520=1000e^{15k}$

$\frac{8250}{1000}=e^{15k}\\8.52=e^{15k}$

taking logarithmic function on both side we have

$15k=ln(8.52)\\k=\frac{ln(8.52)}{15}\\ k=0.1428\\k=0.143$

Hence option A is correct.