Answer:
T = -28.2 °C
Solution:
Data Given;
P = 1820 mmHg = 2.39 atm
V = 5.12 L
m = 19.4 g
R = 0.0821 atm.L.mol⁻¹.K⁻¹
Calculating moles,
n = 19.4 g ÷ 32 g.mol⁻¹
n = 0.606 mol
Assuming that the oxygen gas is acting perfectly, then according to Ideal Gas Equation,
P V = n R T
Solving for T,
T = P V / n R
Putting values,
T = (2.39 atm × 5.12 L) ÷ (0.606 mol × 0.0821 atm.L.mol⁻¹.K⁻¹)
T = 244.7 K
Or,
T = -28.2 °C
