Answer:
The answer is: 'no solution'
Step-by-step explanation:
The given equation is: [tex]3\sqrt{5x-4}=3\sqrt{7x+8}[/tex]
Dividing both sides of the equation by 3, we will get.....
[tex]\sqrt{5x-4}=\sqrt{7x+8}[/tex]
Taking square on both sides.....
[tex](\sqrt{5x-4})^2=(\sqrt{7x+8})^2\\ \\ 5x-4=7x+8\\ \\ 5x-7x=8+4\\ \\ -2x=12\\ \\ x=\frac{12}{-2}=-6[/tex]
Plugging this [tex]x=-6[/tex] back to the given equation......
[tex]3\sqrt{5(-6)-4}=3\sqrt{7(-6)+8}\\ \\ 3\sqrt{-34}=3\sqrt{-34}[/tex]
As we are getting a negative number inside the square root, so the equation becomes imaginary. Thus [tex]x=-6[/tex] is a restricted value.
Hence, there is 'no solution' for this equation.
