Question

A circle has the equation (x-2)^2+y^2=5. Whay are the coordinates of the circles center?

Answer 1

(x-h)^2 + (y-k)^2 = r^2

(x-2)^2 + (y-0)^2 = (rt(5))^2

-h = -2
h = 2

k=0

Center(2, 0)

Answer 2

Answer:

(2,0)

Step-by-step explanation:

Following the circle formula: $(x-h)^2 + (y-k)=r^2$, we can deduce the values of Point(h,k).

The point is (2,0).