Question

QF Q2.) Solve the triangle

Answer 1

C=180-A-B=180-67-53=60deg.

by sine rule

b/sinB=a/sinA
b=a/sinA*sinB
=13/sin(67)*sin(53)
= 11.28

c/sinC=a/sinA
c=a/sinA*sinC
=13/sin(67)*sin(60)
= 12.23

Answer 2

Sum of interior angles in a triangle is 180 deg.

so angle C = 180 - A - B

=180 - 67 - 53

=60deg.

Use the sine rule in a triangle - sinA / a = sinB / b

b = a * sinB / sinA
=13 * sin(53) / sin(67)
=11.3

Similarly sinC / c = sinA / a
c = a * sinC / sinA
=13 * sin(60) / sin(67)
=12.2