Question

Solve the following equation algebraically:

-16=16x^2

How many solutions does this equation have? Explain.

Answer 1

For this case we have the following equation:
 -16 = 16x ^ 2
 Clearing x we have:
 -16 / 16 = x ^ 2
 x ^ 2 = -1
 x = +/- root (-1)
 Rewriting:
 x = +/- i
 Therefore, the solutions are:
 x1 = i
 x2 = -i
 Answer:
 this equation has two solutions:
 x1 = i
 x2 = -i

Answer 2

B. No solution because I got that right