Respuesta :
The mole ratio of PbO2 to water in
Pb + PbO2 +2 H2SO4 = 2PbSO4 + 2H2O is
1 :2
1 mole of Pb reacted with 1 mole of PbO2 and 2 moles of H2SO4 to form 2 moles of PbSO4 and 2 moles of H2O
therefore the mole ratio of Pbo2 to H2O is 1:2
Pb + PbO2 +2 H2SO4 = 2PbSO4 + 2H2O is
1 :2
1 mole of Pb reacted with 1 mole of PbO2 and 2 moles of H2SO4 to form 2 moles of PbSO4 and 2 moles of H2O
therefore the mole ratio of Pbo2 to H2O is 1:2
Taking into account the reaction stoichiometry, the mole ratio of PbO₂ to water PbO₂:H₂O is 1:2.
The balanced reaction is:
Pb + PbO₂ + 2 H₂SO₄ → 2 PbSO₄ + 2 H₂O
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- Pb: 1 mole
- PbO₂: 1 mole
- H₂SO₄: 2moles
- PbSO₄: 2 moles
- H₂O: 2 moles
Then, you can observe that by stoichiometry of the reaction 1 mole of PbO₂ forms 2 moles of water (H₂O).
Finally, the mole ratio of PbO₂ to water PbO₂:H₂O is 1:2.
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