PLEASE HELP WILL GIVE BRAINLIEST! What is the following sum? Assume x > or equal to 0 and y is > or equal to 0.
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Answer:
Option (b) is correct.
The sum of given expression [tex]\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}[/tex] is [tex]2xy\sqrt{y}+2xy^2\sqrt{x}[/tex]
Step-by-step explanation:
Given:Expression [tex]\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}[/tex]
We have to find the sum of the given expression and choose the correct from the given options.
Consider the given expression [tex]\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}[/tex].
[tex]\sqrt{x^2y^3}[/tex] can be written as [tex]\sqrt{x^2y^2y}=xy\sqrt{y}[/tex]
Also, [tex]2\sqrt{x^3y^4}[/tex] can be written as [tex]2\sqrt{x^3y^4}=2\sqrt{x^2x(y^2)^2}=2xy^2\sqrt{x}[/tex]
Now, the given expression becomes,
[tex]\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}[/tex]
[tex]=xy\sqrt{y}+2xy^2\sqrt{x}+xy\sqrt{y}[/tex].
Now, adding like term, terms having same variable with same degree.
[tex]=2xy\sqrt{y}+2xy^2\sqrt{x}[/tex].
Thus, The sum of given expression [tex]\sqrt{x^2y^3}+2\sqrt{x^3y^4}+xy\sqrt{y}[/tex] is [tex]2xy\sqrt{y}+2xy^2\sqrt{x}[/tex]
Answer:
B.) [tex]2xy\sqrt{y} +2xy^{2}+\sqrt{x}[/tex]
Step-by-step explanation:
I jus got it right on edge.