We know that B is a point of tangency, so as known from the problem [tex]\overline{AB}[/tex] is tagent to the circle in this point. We also know that the segment line [tex]\overline{BO}[/tex] is perpendicular (given that this segment is the radius) to the previous tangent, therefore we are in the presence of a right triangle. Then, the following equation is true:
[tex]\overline{AB}^{2}+\overline{BO}^{2}=\overline{AO}^{2}[/tex]
being [tex]\overline{BO}=r[/tex]
Then:
[tex]r^{2}=\overline{AO}^{2}-\overline{AB}^{2}[/tex]
[tex]r=\sqrt{\overline{AO}^{2}-\overline{AB}^{2}}[/tex]
[tex]r=\sqrt{17.4^{2}-7^{2}}[/tex]
[tex]r=15.9[/tex]