Respuesta :

The answer is A. Cu ^2+

Answer : Cu²⁺ ion can be most easily reduced.

Explanation :

Let us write the reduction reactions and the associated standard reduction potentials for the given ions.

1) [tex] Cu^{2+} + 2e^{-}\rightarrow Cu [/tex] [tex] E^{0}_{red}= 0.34 V [/tex]

2) [tex] Zn^{2+} + 2e^{-}\rightarrow Zn [/tex] [tex] E^{0}_{red}= -0.76 V [/tex]

3) [tex] Ni^{2+} + 2e^{-}\rightarrow Ni [/tex] [tex] E^{0}_{red}= -0.26 V [/tex]

4) [tex] Ca^{2+} + 2e^{-}\rightarrow Ca [/tex] [tex] E^{0}_{red}= -2.87 V [/tex]

If we look at the above standard reduction potential values, we see that standard reduction potential is highest for Cu²⁺ ion.

Higher the standard reduction potential, greater is the ability to undergo reduction.

Since Cu²⁺ ion has the highest standard reduction potential, it can be most easily reduced.


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