First off, let's order the values from least to greatest.
121, 122, 125, 126, 132, 135, 136, 136, 138, 140.
Then, let's find the minimum, which is obviously the smallest number, so 121.
Q1 is the number in between the minimum and the median, which will be 125.
The median is the middle number, and since the amount of values is even (10), let's find the median of 132-135, which is 133.5.
Q3 is the number in between the median and the maximum, which will be 136.
Finally, the maximum is obviously the largest number in the group, which is 140, so your answer will be A.
Minimum- 121.
Q1- 125.
Median- 133.5.
Q3- 136.
Maximum- 140.
Hope that helps!