Question

A water balloon is tossed into the air with an upward velocity of 25 ft/s. It’s height h(t) in ft after t seconds is given by the function h(t)=-16^2+25t+3. Show your work. 19. After how many seconds will the balloon hit the ground? (Hint: use the quadratic formula) 20. What will the height be at t=1 second

Answer 1

For this case we have the following encuacion:
 h (t) = - 16t ^ 2 + 25t + 3
 We match zero:
 -16t ^ 2 + 25t + 3 = 0
 Solving the polynomial we have:
 t1 = -0.11197537049727824
 t2 = 1.6744753704972783
 Taking the positive root we have:
 t = 1.67 s
 The height for t = 1 is:
 h (1) = - 16 * (1) ^ 2 + 25 * (1) +3
 h (1) = 12 feet
 Answer:
 The balloon will hit the ground in: 
 t = 1.67 s
 the height will be at t = 1 second:
 h (1) = 12 feet