Question

what is the point slope form of a line with a slope 4/5 that contains the point (-2,1)

Answer 1

$Use:\ y-y_1=m(x-x_1)$

$We\ have:\\\\m=\dfrac{4}{5}\\\\(-2;\ 1)\to x_1=-2\ and\ y_1=1$

$Substitute:\\\\y-1=\dfrac{4}{5}(x-(-2))\\\\\boxed{B.\ y-1=\dfrac{4}{5}(x+2)}$