Question

A line contains points M(1, 3) and N(5, 0). What is the slope of MN?

Answer 1

For this case we have the following points:
 M (1,3)
 N (5.0)
 The slope of the line is given by:
 m = (y2-y1) / (x2-x1)
 Substituting values we have:
 m = (0-3) / (5-1)
 Rewriting we have:
 m = -3 / 4
 Answer:
 The slope of the line is:
 m = -3 / 4

Answer 2

The slope of the line that points M and N lies on is $-\frac{3}{4}$

Given:

$M(1, 3)\\N(5, 0)$

Formula for slope of a line is:

$slope (m) = \frac{y_2 - y_1}{x_2 - x_1}$

Let,

$M(1, 3) = (x_1, y_1)\\N(5, 0) = (x_2, y_2)$

Substitute

$Slope(m) = \frac{0-3}{5-1} \\= \frac{-3}{4} \\= -\frac{3}{4}$

Therefore, the slope of the line that contains M(1, 3) and N(5, 0) is: $-\frac{3}{4}$

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