Question

how many real solutions does the system have? {y=−3x−3y=x2−3x+5 Enter your answer in the box

Answer 1

we have that
y=−3x−3
y=x²−3x+5

using a graph tool
see the attached figure


the system has zero real solutions, the graphics do not intercept

Answer 2

Answer:

Zero real solutions does the system have.

Step-by-step explanation:

Given the system of equations:

$y = -3x-3$

$y = x^2-3x+5$

Equate these equations we have;

$-3x-3 = x^2-3x+5$

Add 3x to both sides we have;

$-3 = x^2+5$

Subtract 5 from both sides we have;

$x^2 = -8$

⇒$x = \pm \sqrt{-8}=\pm 8i$

$x = \pm 8i$, where i is the imaginary part.

both solution are imaginary.

Therefore, the system of equation does not have any real solutions.