Respuesta :
Answer:
3 electrons are gained by one nitrogen atom in the formation of K₃N.
Explanation:
The reaction is as follow,
6 K + N₂ → 2 K₃N
Oxidation of K,
K → K⁺ + 1 e⁻
Or,
6 K → 6 K⁺ + 6 e⁻
In oxidation reaction potassium atom transfers one electron per atomn and six electrons per six atoms.
Reduction of N;
N₂ + 6 e⁻ → 2 N³⁻
In reduction reaction one molecule of N₂ gains six electrons and 3 electrons per one atom
3 electrons are gained by one nitrogen atom in the formation of K₃N.
Explanation:
The reaction is as follow,
6 K + N₂ → 2 K₃N
Oxidation of K,
K → K⁺ + 1 e⁻
Or,
6 K → 6 K⁺ + 6 e⁻
In oxidation reaction potassium atom transfers one electron per atomn and six electrons per six atoms.
Reduction of N;
N₂ + 6 e⁻ → 2 N³⁻
In reduction reaction one molecule of N₂ gains six electrons and 3 electrons per one atom
Zero valence electrons are transferred from nitrogen to potassium in the formation of the compound potassium nitride.
Electrons are transferred from potassium to nitrogen.
What are valence electrons?
Valence electrons are present in the outermost cells, which are capable of forming chemical bonds.
The equation is
[tex]\bold{ 6 K + N_2 = 2 K_3N}[/tex]
[tex]\bold{K = K^+ + e^-}\\\\\bold{NO_3 + e^- = NO^3 ^-}[/tex]
The electrons are transferred by potassium to nitrogen.
Thus, the number of electrons transferred by nitrogen to potassium is zero.
Learn more about valence electrons, here:
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