Question

Choose the correct answer. two cars leave phoenix and travel along roads 90 degrees apart. if car 1 leaves 30 minutes earlier than car 2 and averages 42 mph and if car 2 averages 50 mph, how far apart will they be after car 1 has traveled 3.5 hours? miles.

Answer 1

The equation of movement for each car is given by:
 Car 1:
 d1 = v1 * t1
 Substituting values:
 d1 = 42 * 3.5
 d1 = 147 miles
 Car 2:
 d2 = v2 * t2
 d2 = v2 * (t1 + 0.5)
 Substituting values:
 d2 = 50 * (3.5 + 0.5)
 d2 = 200 miles
 The distance between the cars is:
 d = root ((d1) ^ 2 + (d2) ^ 2)
 d = root ((147) ^ 2 + (200) ^ 2)
 d = 248.2 miles
 Answer:
 They will be 248.2 miles far.

Answer 2

The answer is 210 miles.