Answer:
20 L of Cl₂
Solution:
The reaction is as follow,
H₂C₂ + 2 Cl₂ → H₂C₂Cl₄
According to equation,
167.84 g (1 mole) H₂C₂Cl₄ is produced by = 44.8 L (2 mole) of Cl₂
So,
75 g of H₂C₂Cl₄ will be produced by = X L of Cl₂
Solving for X,
X = (44.8 L × 75 g) ÷ 167.84 g
X = 20 L of Cl₂