Question

A 10.-newton force is required to hold a stretched spring 0.20 meter from its rest position. What is the potential energy stored in the stretched spring?

Answer 1

$F_{r}$ = 10 N
x = 0.2 m

$F_{r}$ = -Kx

-K = $\frac{10 N}{0.2 m}$

K = -50$\frac{N}{m}$