Question

which shows how to find the value of this expression when x=-2 and y=5? (3x^3y^-2)^2

Answer 1

x=-2 and y=5

(3x^3y^-2)^2=[3(-2)^3 (5)^(-2)]^2=[3(-8)/(5)^2]^2=(-24/25)^2=(-24)^2/(25)^2

(3x^3y^-2)^2=576/625

Answer: The value of the expression is 576/625

Answer 2

Answer:

Option 1   -   32(-2)6/54