For the first two problems, you can use a calculator to check your work.
3) 27/11
11 goes into 27 two times. The whole number is 2.
11 × 2 = 22
Subtract 27 - 22 = 5.
You have 5/11 left over, so the answer is 2[tex] \frac{5}{11} [/tex].
4) The least common multiple of 5 and 25 is 25.
The least common multiple is the number that can be divided by both 5 and 25.
25 can be divided by 5 and 25.
5) 5/12 - 2/4
Make 2/4 have a common denominator with 5/12. Multiply the top and bottom number of 2/4 by 3.
2/4 = 6/12
Now you can solve: 5/12 - 6/12 = -1/12
The answer is -1/12.
6) 12/15 × 5/24
You can multiply straight across.
[tex] \frac{12}{15} [/tex] × [tex] \frac{5}{24} [/tex] = 60/360
You can simplify 60/360 by dividing both sides by 60.
60/360 = 1/6
The answer is 1/6.
7) 2/7, 3/7, __, 5/7
This is a pattern question.
4/7 is correct, you are just adding 1 to the numerator each time.
8) 9/27 ÷ 3/9
Use Keep, Change, Flip.
Keep the 9/27,
Change the ÷ sign to a × sign.
Flip 3/9 to 9/3.
Your new equation is: 9/27 × 9/3. Now solve.
9/27 × 9/3 = 81/81 ⇒ 1
The answer is 1.
9) 6[tex] \frac{1}{5} [/tex] ÷ [tex] \frac{9}{10} [/tex]
Change 6 1/5 to an improper fraction ⇒ 31/5
Use the Keep, Change, Flip method again.
31/5 × 10/9 = 310/45
310/45 = 62/9
The answer is 62/9 or 6[tex] \frac{8}{9} [/tex].
