Question

PLEASE PLEASE IF YOU CAN SOLVE THIS THEN HELP :( Will give brainliest! A shot put is thrown upward with a velocity of 35 ft./sec. at a height of 4 ft. and an angle of 40°. How long will it take for the shot put to be a horizontal distance of 40 ft. from the person throwing it? Acceleration due to gravity is 32 ft./s^2 round your answer to the nearest hundreth

Answer 1

The horizontal velocity of a projectile is constant, and in this case, it is calculated as v_0 cos(theta) = (35 ft/s) cos(40) = 26.81 ft/s. Therefore, for the shot put to have a horizontal distance of 40 ft, it will take (40 ft) / (26.81 ft/s) = 1.49 s.
Gravity does not affect horizontal velocity, only vertical velocity.

Answer 2

Answer:

1.49 sec

Step-by-step explanation:

x=v cos(theta)*t

40=35 cos40 *t,  

t=1.49