Question

Which point lies on the graph of the boundary line of the inequality 3y + 4x < 12?

Answer 1

$3 y + 4 x \ \textless \ 12$

Subtract 4 x from both sides

$3y+4x-4x \ \textless \ 12-4x$$3y\ \textless \ 12 - 4x$

Divide both sides by 3 :

$\frac{3y}{3} \ \textless \ \frac{12-4x}{3}$

$y\ \textless \ \frac{12-4x}{3}$


Image attached

hope this helps!