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a sodium atom has the electron configuration of [ 2,8,1 ] before bonding with a chlorine atom which has the electron configuration of [ 2,8,7 ].
because sodium becomes a one plus ion ( +1 ), it must lose an electron to become stable therefore when bonded the electron configuration becomes [ 2,8 ] this is the same as the noble gas, Neon [ 2,8 ].
because chlorine becomes a minus one ion ( -1 ), it must gain an electron to become stable therefore when boded the electron configuration becomes [ 2,8,8 ] this is the same as the noble gas, Argon [ 2,8,8 ].
hope this helps :)
because sodium becomes a one plus ion ( +1 ), it must lose an electron to become stable therefore when bonded the electron configuration becomes [ 2,8 ] this is the same as the noble gas, Neon [ 2,8 ].
because chlorine becomes a minus one ion ( -1 ), it must gain an electron to become stable therefore when boded the electron configuration becomes [ 2,8,8 ] this is the same as the noble gas, Argon [ 2,8,8 ].
hope this helps :)
The compound are the same as those of Neon and Argon.
• In order of their density, the noble gases are helium, neon, argon, krypton, xenon, and radon.
• They are known as noble gases as they do not react with anything. Due to this they are also known as inert gases.
• When the atom of sodium reacts with an atom of chlorine and produce a compound, the atom of sodium loses one electron from its outermost shell and gives the electronic configuration of neon, that is, 2,8.
• On the other hand, the atom of chlorine gains one electron on its outermost shell and gives the electronic configuration of argon as 2,8,8.
Thus, the correct answer is neon and argon.
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