Respuesta :
So,
[tex] \frac{ \sqrt{5} }{2} - \sqrt{5} + \frac{2}{2} +\sqrt{5}[/tex]
[tex] \frac{1}{2}\sqrt{5} - \sqrt{5} + \frac{2}{2} +\sqrt{5}[/tex]
First, we have to simplify the expression.
We can see that there is a negative square root of 5 and a positive square root of 5. They cancel out. In addition, we know that two-halves are equal to 1.
[tex] \frac{1}{2}\sqrt{5} + \frac{2}{2}[/tex]
[tex] \frac{1}{2}\sqrt{5} + 1[/tex]
Since the square root of 5 can be thought of as 5 to the one-half power, we should evaluate that first.
[tex]\sqrt{5}=2.23606797749978969640\ or\ approximately\ 2.236[/tex]
Substitute 2.236 for the square root of 5.
[tex] \frac{1}{2}(2.236) + 1[/tex]
Multiply.
1.118 + 1
Add.
2.118
So the expression is approximately equal to 2.118 (exactly 2.1180339887498948482045868343656).
[tex] \frac{ \sqrt{5} }{2} - \sqrt{5} + \frac{2}{2} +\sqrt{5}[/tex]
[tex] \frac{1}{2}\sqrt{5} - \sqrt{5} + \frac{2}{2} +\sqrt{5}[/tex]
First, we have to simplify the expression.
We can see that there is a negative square root of 5 and a positive square root of 5. They cancel out. In addition, we know that two-halves are equal to 1.
[tex] \frac{1}{2}\sqrt{5} + \frac{2}{2}[/tex]
[tex] \frac{1}{2}\sqrt{5} + 1[/tex]
Since the square root of 5 can be thought of as 5 to the one-half power, we should evaluate that first.
[tex]\sqrt{5}=2.23606797749978969640\ or\ approximately\ 2.236[/tex]
Substitute 2.236 for the square root of 5.
[tex] \frac{1}{2}(2.236) + 1[/tex]
Multiply.
1.118 + 1
Add.
2.118
So the expression is approximately equal to 2.118 (exactly 2.1180339887498948482045868343656).