Question

simplify log (x2-y2)- log (x-y)=

Answer 1

Using the law of logarithm.  LogA - LogB =  Log(A/B)

log(x²-y²) - log(x-y) = log((x²-y²)/(x-y))

Note by difference of two squares, (x²-y²) = (x-y)(x+y)

Simplifying (x²-y²)/(x-y) = (x-y)(x+y)/(x-y) = (x+y)

Therefore log(x²-y²) - log(x-y) = log((x²-y²)/(x-y)) = log((x-y)(x+y)/(x-y)) = log(x+y)