Question

Hello everyone, please explain this with details. Jay traveled from Miami to Jacksonville, a distance of 320 miles. He left Miami at
8:00 A.M., stopped for lunch for 30 minutes, and stopped for two 15 minute breaks at rest
areas. He arrived in Jacksonville at 2:15 P.M. What was his average rate of speed during
his travel time?

Answer 1

Travel from 8 AM to 2:15 PM is a total of 6 hours and 15 minutes. If you subtract the 30 minute lunch and two 15 minute breaks you are left with 5 hours and 15 minutes or 5.25 hours. To get his average speed divide 320 miles by 5.25 hours

320 ÷ 5.25 = 60.9 mph or 61 mph rounded to the nearest one.